If it's not what You are looking for type in the equation solver your own equation and let us solve it.
X^2-50X+100=00
a = 1; b = -50; c = +100;
Δ = b2-4ac
Δ = -502-4·1·100
Δ = 2100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2100}=\sqrt{100*21}=\sqrt{100}*\sqrt{21}=10\sqrt{21}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-10\sqrt{21}}{2*1}=\frac{50-10\sqrt{21}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+10\sqrt{21}}{2*1}=\frac{50+10\sqrt{21}}{2} $
| 0.50x+0.20=3.30 | | 3(3x+4)+5=71 | | s+12.5=14s= | | 3v+3=-8+4v | | 17v=45+8v | | 3(3y+7)=66 | | 7n-11=-20n-11 | | 2x-10.8=9.4 | | 3-d=-10 | | 4r+7-r=5+3r | | 5(6n-4)=40 | | 5x+4+23=8-14 | | 9(h-88)=72 | | -3w+5=-72+8w | | (–7+2k)(6)= | | 1000=50x+500 | | 19+19t=20t | | y+(-5)=3 | | -130=6+4(7x-6) | | Y=-0.4x^2-3x+1 | | f/6+46=50 | | 180=2x+13 | | -12(-5-b)=1/3(b+16) | | 16u=9u+42 | | )A-19x-19=-19x-19−19x−19=−19x−19 | | 6q+17=8q-15 | | 27=3n-12 | | 11=-2t-5 | | -4(9+x=44 | | A-19x-19=-19x-19−19x−19=−19x−19 | | 7p+14=56 | | 13/4b=24 |